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Question

200 mL of a solution mixture NaOH and Na2CO3 was first titrated with phenolphthalein and N/10 HCl 17.5 mL of HCl was required for the end point. After this methyl orange was added and 2.5 mL of same HCl was again required for next end point. Find out the mass of NaOH and Na2CO3.

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Solution

200ml mixture of NaOH & Na2CO3
Let NaOH be x moles, Na2CO3 be y moles with hph indicator
we detect
x+y moles =110×17.51000=1.75 millimoles
next with methyorange
y moles =110×2.5100=0.75 millimoles
x=1.5 millimoles
y=0.25 millimoles
weight of NaOH=1.5×40×103=60mg
weight of Na2CO3=0.25×106×103=26.5mg

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