A mixture of 1-iodoethane and 1-iodopropane is treated with sodium metal and dry ether to carry out Wurtz reaction. Which of the following hydrocarbons will be formed?

Propane + Hexane

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Ethane + Propane

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Butane + Propane

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Butane + Pentane + Hexane

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Solution

The correct option is D Butane + Pentane + Hexane
In Wurtz reaction, if two different alkyl halides are treated with sodium metal in presence of dry ether then a mixture of three different products is obtained.
Thus, when a mixture of 1-iodoethane and 1-iodopropane is treated with sodium metal and dry ether, butane, pentane, and hexane will be obtained.
$C H_{3} C H_{2} I 1 - i o d o e t h a n e + I C H_{2} C H_{3} 1 - i o d o e t h a n e N a - --- \to - 2 N a I C H_{3} C H_{2} C H_{2} C H_{3} B u t a n e$
$C H_{3} C H_{2} I 1 - i o d o e t h a n e + I C H_{2} C H_{2} C H_{3} 1 - i o d o p r o p a n e N a - --- \to - 2 N a I C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} P e n t a n e$
$C H_{3} C H_{2} C H_{2} I 1 - i o d o p r o p a n e + I C H_{2} C H_{2} C H_{3} 1 - i o d o p r o p a n e N a - --- \to - 2 N a I C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} C H_{3} H e x a n e$

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