CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A mixture of 2 moles of CH4 & 34 gms of H2S was placed in an evacuated container, which was then heated to & maintained at 727C. When equilibrium was established in the gaseous reaction CH4+2H2SCS2+4H2; the total pressure in the container was 0.92 atm & the partial pressure of hydrogen was 0.2 atm. What was the volume of the container?

A
298L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
400L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
330.18L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
480L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 298L
CH4+2H2SCS2+4H2
2 1
2-x 1-2x x 4x
pH2=4xP/(3+2x);0.2(3+2x)=4x×0.92
x=0.1875.
So volume of container is V=nRT/P=4×0.18×0.083×1000/0.2=298L.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon