A mixture of CO and CO 2 is found to have a density of 1-5 g - litre at 30- C and 730 torr- What is the composition of mixture-

Molar mass of CO = (12.01 + 16.00) g/mol = 28.01 g/mol Molar mass of CO_2 = (12.01 + 16.00 × 2) g/mol = 44.01 g/mol Assume that the mixture contains y% of CO an ...

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Byju's Answer

Standard XII

Chemistry

Boyle's Law

A mixture of ...

Question

A mixture of CO and $C O_{2}$ is found to have a density of 1.5g/litre at $30^{\circ} c$ and 730 torr. What is the composition of mixture?

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Solution

Molar mass of $C O = (12.01 + 16.00) g / m o l = 28.01 g / m o l$
Molar mass of $C O_{2} = (12.01 + 16.00 \times 2) g / m o l = 44.01 g / m o l$
Assume that the mixture contains $y % o f C O a n d (1 - y %) o f C O_{2} .$
Average molar mass $= [28.01 \times y % + 44.01 \times (1 - y %)]$ g/mol = (44.01 - 0.16y) g/mol
For the gaseous mixture :
Pressure, P = 740 mmHg
Density, d = 1.50 g/L
Molar mass, M = (44.01 - 0.16y) g/mol
Gas constant, R = 62.36 mmHg L / (mol K)
Temperature, T = (273 + 20) K = 293 K

$P V = n R T$
$P V = (\frac{m}{M}) R T$
$P M = (\frac{m}{V}) R T$
$P M = d R T$
$M = \frac{d R T}{P}$
$44.01 - 0.16 y = 1.50 \times 62.36 \times \frac{293}{740}$
44.01 - 0.16y = 37.04
0.16y = 6.97
y = 43.6
100 - y = 56.4
The mixture contains $43.6 %$ of CO and $56.4 % o f C O_{2}$

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A mixture of CO and CO2 is found to have a density of 1.5g/litre at 30∘c and 730 torr. What is the composition of mixture?

A mixture of CO and $C O_{2}$ is found to have a density of 1.5g/litre at $30^{\circ} c$ and 730 torr. What is the composition of mixture?