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Question

# A mixture of CO and CO2 is found to have a density of 1.5 gm/lt at 30∘C and 730 torr. The composition of the mixture is in terms of mole percentage is

A
CO = 27.73 and CO2 = 72.27
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B
CO = 32.18 and CO2 = 67.82
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C
CO = 35 and CO2 = 65
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D
CO = 30 and CO2 = 70
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Solution

## The correct option is B CO = 32.18 and CO2 = 67.82 Molecular mass of the mixture M = dRTP==1.5×0.0821×303×760730=38.85gm/mol Let the total number of moles be 'x'. Let 'x' = no. of moles of CO.Then no. of moles of CO2 = (1 - x) Molecular Mass of mixture = x × 28 + (1 - x)44 = 38.85 ⇒ x = 0.3218 % of CO = 32.18 and % CO2 = 67.82

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