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Dalton's Law of Partial Pressures

A mixture of ...

Question

A mixture of $C_{2} H_{2}$ and $C_{3} H_{8}$ occupied a certain volume at 80 $m m$ $H g$ . The mixture was completely burnt to $C O_{2}$ and $H_{2} O$ . When the pressure of $C O_{2}$ was found to be 230 $m m$ $H g$ at the same temperature and volume, the fraction of $C_{2} H_{2}$ in mixture is:

A

0.125

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B

0.5

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C

0.85

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D

0.25

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Solution

The correct option is A 0.125
Let pressure of $C_{2} H_{2}$ $= x$

pressure of $C_{3} H_{8}$ $= 80 - x$

$C_{2} H_{2} + 5 / 2 O_{2} \to 2 C O_{2} + H_{2} O$

$C_{3} H_{8} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O$

Pressure of $C O_{2}$ $= 2 x + 3 (80 - x) = 230$

$x = 10$

Fraction 0f $C_{2} H_{2} = 10 / 80 = 0.125$

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