A mixture of equal amounts of calcium carbonate and sodium carbonate was heated till there is no further loss in weight. If the gaseous product obtained occupied a volume of $5.6$ L at STP, find out the initial weight of the mixture.

$100$ g

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$50$ g

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$75$ g

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$25$ g

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Solution

The correct option is D
$25$ g

Explanation of correct option:
The reaction for sodium carbonate and calcium carbonate is given below
Now, from the above reactions, an equal amount of carbon dioxide is produced. So, from each reaction the carbon dioxide produced will be $5.6 / 2 = 2.8$ L.
106 g of ${Na}_{2} {CO}_{3}$ will give $22.4$ L of ${CO}_{2}$
So, $2.8 L {CO}_{2}$ = $\frac{106}{22.4} \times 2.8 \approx 13$ g
and, 100 g of ${CaCO}_{3}$ will give $22.4$ L of ${CO}_{2}$
So, $2.8 L {CO}_{2}$ = $\frac{100}{22.4} \times 2.8 \approx 12$ g
So, the initial quantity of the mixture is $13 + 12 = 25$ g

Hence, the correct option is (D).

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A mixture of equal amounts of calcium carbonate and sodium carbonate was heated till there is no further loss in weight. If the gaseous product obtained occupied a volume of 5.6L at STP, find out the initial weight of the mixture.

A mixture of equal amounts of calcium carbonate and sodium carbonate was heated till there is no further loss in weight. If the gaseous product obtained occupied a volume of $5.6$ L at STP, find out the initial weight of the mixture.