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Oxidising Reagent and Reducing Reagent

A mixture of ...

Question

A mixture of $n_{1}$ moles each of $N a_{2} C_{2} O_{4}$ and $N a H C_{2} O_{4}$ is titrated separately with $H_{2} O_{2}$ and $K O H$ to reach equivalence point. Which of the following statements is/are correct?

Moles of

H_{2} O_{2}

and

K O H

are

n_{1} + n_{2}

and

n_{2}

respectively.

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Moles of

H_{2} O_{2}

and

K O H

are

n_{1} + \frac{n_{2}}{2}

and

n_{1}

respectively.

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n

-factor of

N a H C_{2} O_{4}

with

K O H

and

H_{2} O_{2}

, respectively, are

1

and

2

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n

-factor of

N a_{2} C_{2} O_{4}

with

H_{2} O_{2}

and

H_{2} O_{2}

and

K O H

, respectively, are

2

and

1

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Solution

The correct options are
A Moles of $H_{2} O_{2}$ and $K O H$ are $n_{1} + n_{2}$ and $n_{2}$ respectively.
C $n$ -factor of $N a H C_{2} O_{4}$ with $K O H$ and $H_{2} O_{2}$ , respectively, are $1$ and $2$ .
$N a_{2} C_{2} O_{4}$ and $N a H C_{2} O_{4}$ both react with $H_{2} O_{2}$ as reducing agent only. ( $n$ -factor for both $= 2$ )
Equivalents of $H_{2} O_{2} =$ Equivalents of $N a_{2} C_{2} O_{4} +$ Equivalents of $N a H C_{2} O_{4}$
$2 \times$ moles of $H_{2} O_{2} = n_{1} \times 2 + n_{2} \times 2$
Moles of $H_{2} O_{2} = \frac{2 (n_{1} + n_{2})}{2} = (n_{1} + n_{2})$
Only $N a H C_{2} O_{4}$ reacts with $K O H$ as acid-base titration, $n$ factor $= 1$ (one $H^{⨁}$ ion).
Equivalents of $K O H =$ Equivalents of $N a H C O_{3}$
$1 \times$ moles of $K O H = n_{2} \times 1$
Moles of $K O H = n_{2}$
$∴$ Moles of $H_{2} O_{2}$ and $K O H$ are $(n_{1} + n_{2})$ and $n_{2}$ .
$n$ -factor of $N a H C_{2} O_{4}$ with $K O H$ and $H_{2} O_{2}$ are $1$ and $2$ respectively.
$n$ -factor of $N a_{2} C_{2} O_{4}$ with $H_{2} O_{2}$ and $K O H$ are $2$ and $2$ respectively.
Hence, options A and C are correct.

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A mixture of n1 moles each of Na2C2O4 and NaHC2O4 is titrated separately with H2O2 and KOH to reach equivalence point. Which of the following statements is/are correct?

A mixture of $n_{1}$ moles each of $N a_{2} C_{2} O_{4}$ and $N a H C_{2} O_{4}$ is titrated separately with $H_{2} O_{2}$ and $K O H$ to reach equivalence point. Which of the following statements is/are correct?