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Methods to Form Lyophobic Colloids

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Question

A mixture of $N a_{2} C O_{3}$ and $N a_{2} S O_{3}$ is treated with dilute $H_{2} S O_{4}$ in a setup such that the gaseous mixture emerging can pass first through a solution of $B a C l_{2}$ and then gases mixture passes through acidified $K_{2} C r_{2} O_{7}$ . Which of the following will you observe?

A

The

B a C l_{2}

solution remains unaffected and the acidified dichromate solution turns green

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B

The

B a C l_{2}

solution gives a white precipitate and the acidified dichromate solution remains unaffected

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C

The

B a C l_{2}

solution gives a white precipitate and the acidified dichromate solution turns green

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D

Both the solutions remain unaffected

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Solution

The correct option is B The $B a C l_{2}$ solution gives a white precipitate and the acidified dichromate solution remains unaffected
Reactions are:
$H_{2} S O_{4} (a q) + N a_{2} C O_{3} (s) \to N a_{2} S O_{4} (a q) + H_{2} O + C O_{2} (g)$

$20 N a_{2} S O_{3} + 10 H_{2} S O_{4} \to 20 N a_{2} S O_{4} + H_{2} O + 10 S O_{2}$

$S O_{2} + B a C l_{2} + H_{2} O \to B a S O_{3} + 2 H C l$
white ppt.

and $C O_{2}$ doesn't react with acidified dichromate solution.

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