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Dalton's Law of Partial Pressures

A mixture of ...

Question

A mixture of non reacting gases exert a pressure of $5$ atm. If one of the gases occupy $40 %$ volume of the mixture, what would be its partial pressure in atm?

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Solution

Volume % of the gas is $40 %$
Mole % of the gas uis $40 %$
Mole fraction $= \frac{40}{100} = 0.4$
$Partialpressure=molefraction×totalpressure$
$= 0.4 \times 5 a t m = 2 a t m$

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