A mixture of sodium carbonate and sodium bicarbonate has a mass of 22 grams. Treatment with excess hydrochloric acid solution liberates 6L of carbon dioxide at 25 degree Celsius and 0.947 ATM pressure. Determine the percent of sodium carbonate in the mixture.

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Solution

Dear Student,

The computation is expressed below,

$P V = n R T n = \frac{P V}{R T} = \frac{0.947 \times 6}{0.08057 \times 298} = 0.23665 m o l m o l a r m a s s o f s o d i u m c a r b o n a t e = 106 \frac{g}{m o l} m o l a r m a s s o f s o d i u m b i c a r b o n a t e = 84 \frac{g}{m o l} m a s s o f s o d i u m c a r b o n a t e = 106 \frac{g}{m o l} \times 0.23665 m o l = \frac{25.0849}{2} = 12.54 g m a s s o f s o d i u m b i c a r b o n a t e = 84 \frac{g}{m o l} \times 0.23665 m o l = \frac{19.8786}{2} = 9.94 g$
Regards.

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