In a reaction 5.3 gram of sodium carbonate reacted with 6 team of ethanoic acid the product were 2.2 gram of carbon dioxide, 0.9 gram of water and 8.2 gram of sodium ethanoate show that these observations are in agreement with the law of conservation of mass. sodium carbonate + ethanoic acid gives sodium ethanoate+ carbon dioxide + water

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Solution

Total mass of reactants = mass of sodium carbonate + mass of ethanoic acid
= 5.3 g + 6 g= 11.3 g
Total mass of products = mass of sodium ethanoate + carbon dioxide + water
= 8.2 g + 2.2 g + 0.9 g = 11.3 g
Thus, the mass of reactants is equal to the mass of products, therefore the observations are in agreement with the law of conservation of mass.

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Question 1
In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

Sodium carbonate + Ethanoic acid

\to

Sodium ethanoate + Carbon dioxide + Water

Q. Sodium carbonate reacts with ethanoic acid to form sodium ethanoate, carbon dioxide and water. In an experiment, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid to form 8.2 g of sodium ethanoate, 2.2 g of carbon dioxide and 0.9 g of water. Show that this data verifies the law of conservation of mass.

Q. Ethanoic acid + Sodium Carbonate

\to

Sodium ethanoate + Carbon dioxide + Water.
If 6 g of acid reacts with 5.3 g of salt, the products are 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium ethanoate. Which law is obeyed ?

In a reaction, In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Which law is applicable in this case?

Q. In a reaction

5.3 g

of sodium carbonate reacted with

6 g

of ethanoic acid. The products were

2.2 g

of carbondioxide,

0.9 g

of water and

8.2 g

of sodium ethanoate. These observations are in agreement with :