Sodium carbonate reacts with ethanoic acid to form sodium ethanoate, carbon dioxide and water. In an experiment, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid to form 8.2 g of sodium ethanoate, 2.2 g of carbon dioxide and 0.9 g of water. Show that this data verifies the law of conservation of mass.

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Solution

$\underset{6 g}{2 {CH}_{3} COOH} + \underset{5.3 g}{{Na}_{2} {CO}_{3}} \to 2 \underset{8.2 g}{{CH}_{3} COONa} + \underset{2.2 g}{{CO}_{2}} + \underset{0.9 g}{H_{2} O}$

Total mass of reactants = 6 g + 5.3 g = 11.3 g
Total mass of products = 8.2 g + 2.2 g + 0.9 g = 11.3 g

The total mass of the reactants = Total mass of the products.

So, from this, we can verify the law of conservation of mass.

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Similar questions

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water

In a reaction, In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Which law is applicable in this case?

Q. Ethanoic acid + Sodium Carbonate

\to

Sodium ethanoate + Carbon dioxide + Water.
If 6 g of acid reacts with 5.3 g of salt, the products are 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium ethanoate. Which law is obeyed ?

Q. In a reaction

5.3 g

of sodium carbonate reacted with

6 g

of ethanoic acid. The products were

2.2 g

of carbondioxide,

0.9 g

of water and

8.2 g

of sodium ethanoate. These observations are in agreement with :

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
Sodium Carbonate + Acetic Acid $\to$ Sodium Acetate + Carbon Dioxide + Water

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2CH3COOH6 g+Na2CO35.3 g →2CH3COONa8.2 g+CO22.2 g+H2O0.9 g Total mass of reactants = 6 g + 5.3 g = 11.3 g Total mass of products = 8.2 g + 2.2 g + 0.9 g = 11.3 g The total mass of the reactants = Total mass of the products. So, from this, we can verify the law of conservation of mass.