A mixture of volatile components A and B has total vapour pressure in torr as P- 254-119-A- where -A is the mole fraction of A in the mixture- Hence- PAo and PBo respectively are in torr-

At a given temperature, the total vapour pressure (in Torr) of a mixture of volatile components A and B is given by P = 120 - 75 XBhence vapour pressure of pure A and B respectively (in Torr) are -

Q. At a given temperature, total vapour pressure in Torr of a mixture volatile components A and B is given by

P_{T o t a l} = 120 - 75 X_{B}

Hence, vapour pressure of pure A and B respectively (in Torr) are ?

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A mixture of volatile components A and B has total vapour pressure (in torr) as P=254−119χA, where χA is the mole fraction of A in the mixture. Hence, PoA and PoB respectively are (in torr):

The correct option is B 135, 254PTotal=PoAχA+PoBχB =PoAχA+PoB(1−χA) =PoB−(PoB−PoA)χAGiven equation =254−119χACompare with the given equation,∴PoB=254,PoB−PoA=119∴PoA=254−119=135Option C is correct.

A mixture of volatile components A and B has total vapour pressure (in torr) as $P = 254 - 119 χ_{A}$ , where $χ_{A}$ is the mole fraction of A in the mixture. Hence, $P_{A}^{o}$ and $P_{B}^{o}$ respectively are (in torr):