A molecule has a permanent electric dipole moment of $5 \times 10^{- 30} C - m$ . If it is supposed to arise from net charge of $+ e$ and $- e$ in the two regions of the molecule, what is their separation?

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Solution

Given: The dipole moment of the molecule is $5 \times 10^{- 30} C . m$ .

The dipole moment is given by:
$= q \times l$
$= 1.6 \times 10^{- 19} \times l$

$\Rightarrow 5 \times 10^{- 30} = 1.6 \times 10^{- 19} \times l$

$\Rightarrow l = \frac{5 \times 10^{- 11}}{1.6} = 3.125 \times 10^{- 11} m$ .

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A molecule has a permanent electric dipole moment of 5 ×10−30 C−m. If it is supposed to arise from net charge of +e and −e in the two regions of the molecule, what is their separation?

Given: The dipole moment of the molecule is 5×10−30C.m.The dipole moment is given by:=q×l=1.6×10−19×l⇒5×10−30=1.6×10−19×l⇒l=5×10−111.6=3.125×10−11 m.

A molecule has a permanent electric dipole moment of $5 \times 10^{- 30} C - m$ . If it is supposed to arise from net charge of $+ e$ and $- e$ in the two regions of the molecule, what is their separation?

Given: The dipole moment of the molecule is $5 \times 10^{- 30} C . m$ .

The dipole moment is given by:
$= q \times l$
$= 1.6 \times 10^{- 19} \times l$

$\Rightarrow 5 \times 10^{- 30} = 1.6 \times 10^{- 19} \times l$

$\Rightarrow l = \frac{5 \times 10^{- 11}}{1.6} = 3.125 \times 10^{- 11} m$ .