Question

An $\text{HCl}$ molecules has a dipole moment of $3.4\times {10}^{-30}\text{C-m}$. Assuming that equal and opposite charges lie on the two atoms to form a dipole, what is the magnitude of this charge? The separation between the two atoms of $\text{HCl}$ is $1.0\times {10}^{-10}\text{m}$.

• A. $1.4\times {10}^{-20}\text{C}$
• B. $2.4\times {10}^{-20}\text{C}$
• C. $3.4\times {10}^{-20}\text{C}$
• D. $4.4\times {10}^{-20}\text{C}$

Answer 1

The correct option is C $3.4\times {10}^{-20}\text{C}$

Given:
$p=3.4\times {10}^{-30}\text{C-m};2l=1.0\times {10}^{-10}\text{m}$

Suppose the two charges of dipole of $\text{HCl}$ is $+q$ and $-q$.

Then, $p=q\left(2l\right)$

using given data

$\Rightarrow 3.4\times {10}^{-30}=q\times 1.0\times {10}^{-10}$

$\Rightarrow q=3.4\times {10}^{-20}\text{C}$

Therefore, option $\left(c\right)$ is correct.