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Dalton's Law of Partial Pressures

'a' moles of ...

Question

'a' moles of $P C l_{5}$ , undergoes, the thermal dissociation as: $P C l_{5} ⇌ P C l_{3} + C l_{2}$ , the mole fraction of $P C l_{3}$ at equilibrium is $0.25$ and the total pressure is $2.0$ atmosphere. The partial pressure of $C l_{2}$ at equilibrium is?

A

2.5

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B

1.0

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C

0.5

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D

None

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Solution

The correct option is A $0.5$
$P C l_{5} \to P C l_{3} + C l_{2}$
Thus mole fraction of $P C l_{3}$ and $C l_{2}$ are equal
so, $x C l_{2} = 0.25$
$P o f C l_{2} = x \times P_{t o t a l} = 0.25 \times 2 = 0.5 a t m$

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