A monkey ascends a greased pole $10$ metres high. He ascends $3$ metres in first minute and slips down $1$ metre in the alternate minute. In which, he reached the top of the pole

10 t h

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12 t h

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13 t h

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11 t h

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Solution

The correct option is A $10 t h$
Distance travelled in $2 m i n u t e s = 3 - 1 = 2 m e t r e s$ , i.e. $1$ metre in one minute.
Let us suppose that he ascends $3 m$ . at the last minute, so that he covers the $9$ metres at the rate of $1$ metre in $1$ minute in $9$ minutes..
Thus, he will reach the top in $10 t h$ minute.

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A monkey ascends a greased pole 10 metres high. He ascends 3 metres in first minute and slips down 1 metre in the alternate minute. In which, he reached the top of the pole

The correct option is A 10thDistance travelled in 2 minutes=3−1=2 metres, i.e. 1 metre in one minute.Let us suppose that he ascends 3 m. at the last minute, so that he covers the 9 metres at the rate of 1 metre in 1 minute in 9 minutes..Thus, he will reach the top in 10th minute.

A monkey ascends a greased pole $10$ metres high. He ascends $3$ metres in first minute and slips down $1$ metre in the alternate minute. In which, he reached the top of the pole