Question

A monkey climbs 4 meters of a pole in 1 minute, but slips 2 meters in next minute in how much time he will reach the top of a pole 15 metres long? Assume that he starts from the bottom of the pole.

• A. 7 min 30 sec
• B. 7 min
• C. 13 min
• D. 12 min 45 sec

Answer 1

Answer: (D)

12 min 45 sec

height of the pole (x) = 15 m
Climbed distance per minute (y) = 4 m
Slips (y) = 2 m in next minute
So, In 2 min he climbs 2 m.
we take, 2 min = 1 unit of time
t = 2 minutes
You can calculate required time by this formula : (we are calculating it for 14 m)
Reqd. Time = [( ht. of pole - slipped distance) / (climbed distance - slipped distance )] *T
= [(x-z) / (y-z)] *t
= [(14-2) / (4-2)] &2
= (12/2) *2
= 6 *2
= 12 minutes
And the last 1 m monkey will climb in 45 second because one he get up did not get slipped down
So, total time = 12 minutes 45 seconds.