Question

A monkey is sitting on a tree limb. The limb exerts a normal force of $48$N and a frictional force of $20$N. Find the magnitude of the total force exerted by the limb on the monkey.

Answer 1

The limb exerts a normal force $48N$ and frictional force of $20N$. Resultant magnitude of the force,
$R=\sqrt{(48{)}^2+(20{)}^2}$
$=\sqrt{2304+400}$
$=\sqrt{2704}$
$=52N$