A mother is three times as old as her daughter. However, after 12 years she will be only two times as old as her daughter. What are their present ages?

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Solution

$Let the present age of daughter = x yrs Present age of mother = 3 x yrs AFTER 12 YEARS : Daughter' s age = (x + 12) yrs Mother' s age = (3 x + 12) yrs Now, according to question : 3 x + 12 = 2 (x + 12) \Rightarrow 3 x + 12 = 2 x + 24 \Rightarrow 3 x - 2 x = 24 - 12 \Rightarrow x = 12 So, daughter' s present age = 12 yrs Mother' s present age = 12 \times 3 = 36 yrs$

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A mother is three times as old as her daughter. However, after 12 years she will be only two times as old as her daughter. What are their present ages?

Let the present age of daughter = x yrsPresent age of mother = 3x yrsAFTER 12 YEARS :Daughter's age = x+12 yrsMother's age = 3x+12 yrsNow, according to question :3x + 12 = 2x+12⇒3x+12 = 2x+24⇒3x - 2x = 24 - 12⇒x = 12So, daughter's present age = 12 yrsMother's present age = 12×3 = 36 yrs