A motor bike- initially moving at 18 km-h- accelerates at a rate of 5 m-s2 and the distance covered by it from start is 87-5 m- Calculate the final velocity-

Step 1:Given data:Acceleration(a)=5 1exm/ 1exs^2.Distance(s)=87.5 mInitial velocity= 18 1exkm/ 1exhr. =18×1000/3600=5 1exm/ 1exs.Step 2:Formula usedv^2=u^2+2 ...

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Standard XII

Physics

Race of Rollers

A motor bike,...

Question

A motor bike, initially moving at 18 km/h, accelerates at a rate of 5 m/s² and the distance covered by it from start is 87.5 m. Calculate the final velocity?

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Solution

Step-1:Given data:
Acceleration(a)=5 $\frac{m}{s^{2}}$
Distance(s)=87.5 m
Initial velocity= $18 \frac{k m}{h r} = 18 \times \frac{1000}{3600} = 5 \frac{m}{s}$
Step 2:Formula used
$v^{2} = u^{2} + 2 a s$ where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance covered.
Step-3: Finding the final velocity
As we know:
$v^{2} = u^{2} + 2 a s v^{2} = {(5 \frac{m}{s})}^{2} + 2 \times 5 \frac{m}{s^{2}} \times 87.5 m v = 30 \frac{m}{s}$
Hence, the final velocity is 30 $\frac{m}{s}$ .

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A motor bike, initially moving at 18 km/h, accelerates at a rate of 5 m/s2 and the distance covered by it from start is 87.5 m. Calculate the final velocity?

A motor bike, initially moving at 18 km/h, accelerates at a rate of 5 m/s² and the distance covered by it from start is 87.5 m. Calculate the final velocity?