A motor boat is going in a river with a velocity V-4i-2j-k-ms-1- lf the resisting force due to stream is F-5i-10j-6k- N- then the power of the motor boat is

The correct option is C 46 W V=(4i⃗ 2j⃗+k⃗)ms^ 1 F=(5i⃗ 10j⃗+6k⃗) N Power =F . v P=(4i⃗ 2j⃗+k⃗)· (5i⃗ 10j⃗+6k⃗) Performing the dot produc ...

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Byju's Answer

Standard XII

Physics

Distance

A motor boat ...

Question

A motor boat is going in a river with a velocity $¯ ¯¯ ¯ V = (4 \to i - 2 \to j + \to k) m s^{- 1}$ . lf the resisting force due to stream is $¯ ¯¯ ¯ F = (5 \to i - 10 \to j + 6 \to k) N$ , then the power of the motor boat is

100 W

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50 W

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46 W

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23 W

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Solution

The correct option is C 46 W
$¯ ¯¯ ¯ V = (4 \to i - 2 \to j + \to k) m s^{- 1}$
$¯ ¯¯ ¯ F = (5 \to i - 10 \to j + 6 \to k) N$
Power $= \to F$ . $\to v$
$P = (4 \to i - 2 \to j + \to k) \cdot (5 \to i - 10 \to j + 6 \to k)$

Performing the dot product we get: $20 + 20 + 6 = 46$ $W$

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A motor boat is going in a river with a velocity ¯¯¯¯V=(4→i−2→j+→k)ms−1. lf the resisting force due to stream is ¯¯¯¯F=(5→i−10→j+6→k)N, then the power of the motor boat is

The correct option is C 46 W¯¯¯¯V=(4→i−2→j+→k)ms−1¯¯¯¯F=(5→i−10→j+6→k)NPower =→F.→vP=(4→i−2→j+→k)⋅(5→i−10→j+6→k)Performing the dot product we get: 20+20+6=46 W

A motor boat is going in a river with a velocity $¯ ¯¯ ¯ V = (4 \to i - 2 \to j + \to k) m s^{- 1}$ . lf the resisting force due to stream is $¯ ¯¯ ¯ F = (5 \to i - 10 \to j + 6 \to k) N$ , then the power of the motor boat is

The correct option is C 46 W
$¯ ¯¯ ¯ V = (4 \to i - 2 \to j + \to k) m s^{- 1}$
$¯ ¯¯ ¯ F = (5 \to i - 10 \to j + 6 \to k) N$
Power $= \to F$ . $\to v$
$P = (4 \to i - 2 \to j + \to k) \cdot (5 \to i - 10 \to j + 6 \to k)$

Performing the dot product we get: $20 + 20 + 6 = 46$ $W$