A motor car approaching a cliff with a velocity of 90 kmph sounds the horn and the echo is heard after 20 seconds. Assuming the velocity of sound in air to be 332 ms−1, the distance between the car and cliff when the horn is sounded is :
A
3570m
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B
3580m
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C
3590m
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D
3560m
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Solution
The correct option is A 3570m ϑ=90km/h=90×10003600m/s=25m/s
Distances travelled by sound wave for echo is 2x−ϑ(t)=V×T 2x−25(20)=332×20 2x=332×20+25(20) x=332×20+25(20)2=3570m