Question

A motorcycle moving with a speed of 5m/s is subjected to an acceleration of 0.2 m/s${}^2$. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.

Answer 1

U = 5 m/sec
a = 0.2
t = 10 sec
USING 1ST EQ OF MOTION,
v = u + at
v = 5 + 0.2×10
v = 5 + 2
v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,


s = 50 + 10
s = 60m

DISTANCE = 60 m