A moving car possesses average velocities of 5 $m s^{- 1}$ , 10 $m s^{- 1}$ , and 15 $m s^{- 1}$ in the first, second, and third seconds, respectively. What is the total distance covered by the car in these $3 s$ ?

15 m

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30 m

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55 m

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None ofthese

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Solution

The correct option is B $30 m$
Average speed in $3 s e c s = \frac{5 + 10 + 15}{3} = 10 m / s$
Distance travelled in $3 s e c = 10 \times 3 = 30 m$

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