Question

a moving car possses average velocities of 5m/s ,10 m/s ,15m/s in the first ,second , and third second respectively what is the total distance covered by the car in these 3s

Answer 1

$$\begin{gathered} \mathrm{Answer} \\ \mathrm{total}\mathrm{distance}\mathrm{covered}=\mathrm{distance}\mathrm{covered}\mathrm{in}\mathrm{first}\mathrm{second}+\mathrm{distance}\mathrm{covered}\mathrm{in}\mathrm{another}\mathrm{second} \\ +\mathrm{distance}\mathrm{covered}\mathrm{in}\mathrm{last}\mathrm{second} \\ \mathrm{S}=5+10+15=30\mathrm{m} \end{gathered}$$