Question

A "moving sidewalk" in a busy airport terminal moves $1m/s$ and is $200m$ long. A passenger steps onto one end and walks, in the same direction as the sidewalk is moving, at a rate of $2.0m/s$ relative to the moving sidewalk. How much time does it take the passenger to reach the opposite end of the walkway? (in seconds)

• A. $66.7$
  
• B. $67.3$
  
• C. $63$
  
• D. $66$
  

Answer 1

The correct option is A $66.7$

assuming velocity of side walk in positive direction.

velocity of side walk wrt ground =$V_{sg}=1m/s$

velocity of passenger wrt side walk =$V_{ps}=2m/s$

velocity of passenger wrt ground is =$V_{pg}=3m/s$

distance to be covered by passenger to reach other end of side walk is 200m

so time taken will be $\frac{200}{3}=66.67$

so option A is best possible.