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Standard VIII

Physics

Domestic Electric Circuits

A multimeter ...

Question

A multimeter reads a voltage of a certain A.C. source as 100 V. What is the peak value of voltage of A.C. source?

200 V

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100 V

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141.4 V

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400 V

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Solution

The correct option is C 141.4 V
A multimeter reads rms value of voltage, thus $V_{r m s} = 100$ V
Peak voltage $V_{o} = \sqrt{2} V_{r m s}$
$∴$ $V_{o} = 1.414 \times 100 = 141.4$ V

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A multimeter reads a voltage of a certain A.C. source as 100 V. What is the peak value of voltage of A.C. source?

The correct option is C 141.4 VA multimeter reads rms value of voltage, thus Vrms=100 VPeak voltage Vo=√2Vrms∴ Vo=1.414×100=141.4 V

The correct option is C 141.4 V
A multimeter reads rms value of voltage, thus $V_{r m s} = 100$ V
Peak voltage $V_{o} = \sqrt{2} V_{r m s}$
$∴$ $V_{o} = 1.414 \times 100 = 141.4$ V