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Newton's Second Law

A net force o...

Question

A net force of 20N acts on a 5 kg mass kept at rest. Distance travelled by the mass in 6 s is

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Solution

Given :
Force=F=20N
mass=5kg
initial velocity= u=0 m/s
t=6s
S=distance=?
We know that, F= ma
a=F/m
=20/5
=4m/s²
Distance travelled = S= ut+1/2at²
=0xt+1/2x4x(6)²
=1/2 (4x36)
=144/2
=72 m
Distance travelled = 72m.

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