Question

A neutral atom has $2K$ electrons, $8L$ electrons and $6M$ electrons. Predict total number of $d-$ electrons

• A. 4
• B. 2
• C. 0.0
• D. 10

Answer 1

The correct option is C 0.0

Total number of electrons $=(2+8+6)=16$
So, Atomic number $=16$
Electronic configuration $=1s^2,2s^{2}2p^6,3s^{2}3p^4$
b) Total number of $s-$ electrons $=1s^2,2s^{2}2p^6,3s^{2}3p^4$
So, total number of $d-$ electrons $=0$