Question

A neutral atom has $2K$ electrons, $8L$ electrons and $6M$ electrons. Predict total number of $p-$ electrons

• A. 4
• B. 6
• C. 8
• D. 10

Answer 1

The correct option is D 10

Total number of electrons $=(2+8+6)=16$
So, Atomic number $=16$
Electronic configuration $=1s^2,2s^{2}2p^6,3s^{2}3p^4$
So, total number of $p-$ electrons $=(2p^6+3p^4)=10$.
Therefore, option(d) is the correct answer.