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Dehydrohalogenation of Dihalides

A nitrile X...

Question

A nitrile $X$ is treated with $L i A l H_{4}$ to obtain compound $Y (C_{2} H_{7} N) .$ In a separate reaction $X$ is hydrolyzed in an acid medium to obtain $Z$ . The product obtained after mixing $Y$ and $Z$ will be?

A

C H_{3} C O N H C H_{2} C H_{3}

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B

C H_{3} C H_{2} C O N H C H_{2} C H_{3}

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C

(C H_{3} C O O^{-}) (C H_{3} C H_{2} N H_{3}^{+})

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D

(C H_{3} C H_{2} C O O^{-}) (C H_{3} N H_{2}^{+})

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Solution

The correct option is C $(C H_{3} C O O^{-}) (C H_{3} C H_{2} N H_{3}^{+})$
$X L i A l H_{4} - ----- \to R e d u c t i o n C_{2} H_{7} N$ (Amine $= Y$ )

$X$ is $C H_{3} - C \equiv N$ (Cyanomethane)
$X H^{+} - - \to Z$
$C H_{3} - C \equiv N H^{+} - - \to C H_{3} C O O H$
$Z = C H_{3} C O O H$

Product after mixing $Y$ and $Z$ is $(C H_{3} C O O^{-}) + (C H_{3} C H_{2} N H_{3}^{+})$ (Substituted Ammonium Carboxylate Salt)

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Dehydrohalogenation of Dihalides

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