A normal woman is married to a colour blind man. The children are excepted to be.

All normal

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sons are colour blind

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All daughters are normal but carrier whereas all sons are normal phenotypically as well as genotypically

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50 %

daughters are colour blind

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Solution

The correct option is C All daughters are normal but carrier whereas all sons are normal phenotypically as well as genotypically
Color blindness is X-linked recessive. Let us say Xc represents defecttive X chromosome carrying color blindness. Chromosome of normal woman will be XX whereas chromosome of color blind man will be XcY. Therefore,
Male progeny will have XY chromosomes. ( all sons are normal phenotypically as well as genotypically).
Female progeny will have XcX chromosomes. (All daughters are normal but carrier).

So, the correct answer is 'All daughters are normal but carrier whereas all sons are normal phenotypically as well as genotypically'.

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(a) one son and one daughter are normal.
(b) sons are colour blind and daughters are normal.
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(d) none of these

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