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Nuclear Fission

A nuclear fis...

Question

A nuclear fission is given below:
$A^{240} \to B^{100} + C^{140} + Q (e n e r g y)$
Let binding energy per nucleon of nucleus $A, B$ and $C$ is $7.6 M e V$ , $8.1 M e V$ and $8.1 M e V$ respectively. Value of $Q$ is : (Approximately)

A

120 M e V

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B

220 M e V

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C

20 M e V

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D

240 M e V

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Solution

The correct option is A $120 M e V$
Q = Related every = $n_{B}^{B} + n_{C}_{C} - n_{A}_{A}$
$Q = 1 ω \times 8.1 M e V + 140 \times 8.1 M e V$
$- 240 \times 7.6 M e V$
$Q = 1944 M e V - 1824 M e V = 120 M e V$

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Similar questions

Q. A nuclear fission is given below

A^{240} \to B^{100} + C^{140} + Q (energy)

.
Let binding energy per nucleon of nucleus

A, B

C

7.6 MeV, 8.1 MeV

8.1 MeV

respectively. Value of

Q

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Q. A heavy nucleus

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240

and binding energy per nucleon

7.6 M e V

is split into two fragments

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Z

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130

the binding energy of nucleons in

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8.5 M e V

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Calculate the energy

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Q. For nuclei with mass number close to 119 and 238, the binding energies per nucleon are approximately 7.6 MeV and 8.6 MeV respectively. If a nucleus of mass number 238 breaks into two nuclei of nearly equal masses, what will be the approximate amount of energy released in the process of fission?

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240

and binding energy per nucleon

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Y

Z

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