A nuclear reaction is given as
$p +^{15} N \to_{Z}^{A} X + n$
If the proton were to collide with the $^{15} N$ at rest, find the minimum KE needed by the proton to initiate the above reaction

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Solution

K.E. of proton to initiate the reaction is equal to Q value of reaction = $△ m c^{2}$
$△ m = m_{(p)} + m_{(N)} - m_{(X)} - m_{(n)} = 1.007825 + 15.000 -^{15} O - n = 1.007825 + 15 - 15.0031 - 1.008665 = - 0.00394$
The K.E needed by the proton to initiate the reaction $Q = - 0.00394 \times 931 M e V = - 3.66 M e V$
Negative sign signifies that this energy is supplied to initiate the reaction.

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A nuclear reaction is given asp+15N→AZX+nIf the proton were to collide with the 15N at rest, find the minimum KE needed by the proton to initiate the above reaction

A nuclear reaction is given as
$p +^{15} N \to_{Z}^{A} X + n$
If the proton were to collide with the $^{15} N$ at rest, find the minimum KE needed by the proton to initiate the above reaction