Question

# A nucleus with mass number 220 initially at rest emits an α -particle.  If the Q value of the reaction is 5.5 MeV, then the kinetic energy of the α -particle is   5.6 MeV 5.4 MeV 4.4 MeV 6.5 MeV

Solution

## The correct option is B 5.4 MeV Given that K1+K2=5.5 MeV From Conservation of Linear Momentum, P1=P2     ⇒√2K1(216m)=√(2K2(4m) As P=√2Km ⇒K2=54K1     …(2) Solving equations (1) and (2), we get K2=KE of α - particle = 5.4 MeV.

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