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Question

A nucleus with mass number 220 initially at rest emits an α -particle.  If the Q value of the reaction is 5.5 MeV, then the kinetic energy of the α -particle is
 


  1. 5.6 MeV

  2. 5.4 MeV

  3. 4.4 MeV

  4. 6.5 MeV


Solution

The correct option is B

5.4 MeV


Given that K1+K2=5.5 MeV

From Conservation of Linear Momentum,

P1=P2    

2K1(216m)=(2K2(4m)

As P=2Km

K2=54K1     (2)

Solving equations (1) and (2), we get K2=KE of α - particle = 5.4 MeV.

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