A nucleus $X$ initially at rest, undergoes alpha decay according to the equation
$92^{X^{A}} \to Z^{Y^{228}} + α$
Then, the values of $A$ and $Z$ are

94, 230

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232, 90

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190, 32

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230, 94

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Solution

The correct option is B $232, 90$
Here, $α =$ $_{2} H e^{4}$
Thus, $_{92} X^{A} \to_{Z} Y^{228} +$ $_{2} H e^{4}$
For balance the equation, $A = 228 + 4 = 232$ and $92 = Z + 2$ or $Z = 90$
Thus, option B will be the right option.

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A nucleus X initially at rest, undergoes alpha decay according to the equation 92XA→ZY228+αThen, the values of A and Z are

The correct option is B 232,90Here, α= 2He4Thus, 92XA→ZY228+ 2He4For balance the equation, A=228+4=232 and 92=Z+2 or Z=90Thus, option B will be the right option.

A nucleus $X$ initially at rest, undergoes alpha decay according to the equation
$92^{X^{A}} \to Z^{Y^{228}} + α$
Then, the values of $A$ and $Z$ are

The correct option is B $232, 90$
Here, $α =$ $_{2} H e^{4}$
Thus, $_{92} X^{A} \to_{Z} Y^{228} +$ $_{2} H e^{4}$
For balance the equation, $A = 228 + 4 = 232$ and $92 = Z + 2$ or $Z = 90$
Thus, option B will be the right option.