A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three α-particle in succession. The group of the periodic table to which the resulting daughter element would belong is
A
Group 14
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B
Group 16
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C
Group 4
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D
Group 6
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Solution
The correct option is B Group 14 After 3 - alpha decay atomic number decreases by 6. Parent atom was in the 2nd group so the daughter will belong to the 14th group since the atomic number decreases by 6.