The correct option is C
23300
Total numbers from 201 to 500 are 300.
Let A be the event of choosing the number between 201 and 500 such that it is a multiple of 13.
The numbers between 201 and 500 that are multiples of 13 are 208,221,234,…,494.
Now, these numbers form an AP with a = 208 and d = 13.
Also, last term, l=a+(n–1)d⇒494=208+(n–1)×13⇒286=(n–1)×13⇒n=23
∴ Number of outcomes favourable = 23
P(A)=Number of outcomes favourable to ATotal number of outcomes=23300
Hence, the correct answer is option c.