A number lies between 20 and 30. If 47 and 92 are divided by the number, then the remainder are 3 and 4 respectively. What is the number?

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Solution

STEP 1:divide $47$ by $22$
According to division algorithm,
Dividend = Divisor x Quotient + remainder
$47 = 22 \times 2 + 3$
STEP 2:divide $92$ by $22$
Dividend = Divisor x Quotient + remainder
$92 = 22 \times 4 + 4$
Therefore ,required whole number is $22$

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A number lies between 20 and 30. If 47 and 92 are divided by the number, then the remainder are 3 and 4 respectively. What is the number?

STEP 1:divide 47 by 22According to division algorithm,Dividend = Divisor x Quotient + remainder 47=22×2+3STEP 2:divide92by 22Dividend = Divisor x Quotient + remainder 92=22×4+4Therefore ,required whole number is 22

STEP 1:divide $47$ by $22$
According to division algorithm,
Dividend = Divisor x Quotient + remainder
$47 = 22 \times 2 + 3$
STEP 2:divide $92$ by $22$
Dividend = Divisor x Quotient + remainder
$92 = 22 \times 4 + 4$
Therefore ,required whole number is $22$