A number of moles of oxygen present in 0.3 moles of oxalic acid dihydrate $(C O O H)_{2} .2 H_{2} O$ are:

9

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18

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0.9

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1.8

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Solution

The correct option is C $1.8$
One molecule of oxalic acid dihydrate contains six oxygen atoms.
Thus, one mole of oxalic acid dihydrate will contain six moles of oxygen atoms.
Hence, the number of moles of oxygen present in 0.3 moles of oxalic acid dihydrate is $0.3 \times 6 = 1.8$ .
Option $D$ is correct.

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