Number of gram atoms of oxygen present in $0.3 m o l e$ of $(C O O H)_{2} .2 H_{2} O$ is

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0.9

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1.8

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Solution

The correct option is D
1.8

No. of gram atoms = no. of moles $\times$ $6$ (number of oxygen atoms)

= $0.3 \times 6$ = $1.8$

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