A number of three digits in the septenary scale is represented in the nonary scale by the same three digits in reverse order; if the middle digit in each case is zero, find the value of the number in the denary scale.
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Solution
Let the number in septenary scale be a0b and in nonary scale be b0a
Now if we convert both of them to denary scale we have,
49a+b=81b+a⇒48a=80b⇒3a=5b
The only single digit number is possible when a=5 and b=3