Question

The sum of a three digit number and the number formed by the reversing its digits (if the middle digit is 0) is always divisible by 101

• A. 12
• B. 11

Answer 1

The correct option is A

12

Let abc be the number.
Thus abc = 100a + 10b + c
The number obtained by reversing the number is cba.
cba = 100c + 10b + a

Adding the two numbers we get, abc + cba = (100a + 10b + c) + (100c + 10b + a) = 101a + 20b + 101c

Since middle digit is 0, the sum will be 101(a+c), which is divisible by 101.