Question

A p.d. of 4 V is applied to two resistors of 6 Ω and 2 Ω connected in series. Calculate:

(a) the combined resistance
(b) the current flowing
(c) the p.d. across the 6 Ω resistor

Answer 1

(a) When two resistors are connected in series, their resultant resistance is given by
R = R₁+ R₂
Here, R₁=6 $\mathrm{\Omega }$,
R₂=2 $\mathrm{\Omega }$
Therefore
The resulatant resistance, R = 6 + 2 = 8 Ω

(b) The current flowing through circuit is:
V = IR
I = V/R = 4/8
I = 0.5 A

(c) The p.d. across the 6 Ω resistor is:
V = 0.5 A x 6 Ω = 3 V