A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2m/s2. He reaches the ground with a speed of 3m/s. At what height, did he bail out?
A
91m
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B
182m
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C
293m
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D
111m
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Solution
The correct option is C293m A→B v2=u2+2as v2=0+2×9.8×50 v=√980m/s From B→C V2=u2+2as (3)2=980−2×2×s s=242.75 Total height =242.72+50=292.75≈293m.