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Question

A parallel beam of light of wavelength 4000A° passes through a slit of width 5×10-3m. The angular spread of the central maxima in the diffraction pattern is


A

1.6×10-3rad

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B

1.6×10-4rad

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C

3.2×10-3rad

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D

3.2×10-4rad

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Solution

The correct option is B

1.6×10-4rad


Step 1: Given data

The wavelength of the given light, λ=4000A°

Slit width, a=5×10-3m

Step 2: Formula Used

The half angular width of central maxima,

sinθ=λa

Step 3: Calculation

The half angular width of central maxima,

sinθ=λaθ=λa(sinθθ)

Angular spread of the central maxima in the diffraction pattern

=2θ=2λa=2×4000×10-105×10-3=1.6×10-4rad

Therefore, the angular spread of the central maxima in the diffraction pattern is 1.6×10-4rad.

Option B is correct.


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