Question

A parallel plate air capacitor is charged to a potential difference of V volt. After disconnecting the charging battery, the distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates

• A. decreases
• B. does not change
• C. becomes zero
• D. increases

Answer 1

The correct option is D increases

$C=\frac{{\epsilon }_{0}A}{d};Q=CV$

If d increases, C decreases.

For a given charge Q, $C\alpha \frac{1}{V}$

As C decreases, V increases