A parallel plate air capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by $Q_{0}, V_{0}, E_{0},$ and $U_{0}$ respectively. A dielectric slab is now introduced to fill the space between the plates with the battery still in connection. The corresponding quantities now given by $Q, V, E$ and $U$ are related to the previous one as

Q > Q_{0}

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V > V_{0}

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E > E_{0}

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U > U_{0}

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Solution

The correct options are
A $Q > Q_{0}$
D $U > U_{0}$

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Q. A parallel plate capacitor is connected to a battery. The quantities charge, voltage, electric field and energy associated with this capacitor are given by

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